換熱器的計算---請教

baboon9105

最近單位上新的項目，要選擇換熱器，但是如何計算？板式和管式有啥區別？

olive3000

管式的不好，建議選用板式的。

hemei

管式的冷卻面積沒有板式冷卻面積大

天涯125

可以查閱化工版的機械設計手冊第4冊上面有詳細的介紹換熱面積的算法

13572593532

板式的換熱效率高,不過最好選擇好一些的制造廠家.小的可以用管式的劃算.

液壓青年

這得看你需要得散熱功率是多大，一般大的用板式散熱器

開達

COOLER
SELECTION
Designation:
PV = Power loss [kW]
P01 = Specific cooling capacity [kW/°C]
V = Tank contents [l]
. l: h0 S9 e! Z) h! |. uρoil = Density of the oil [kg/l]
( ^# e+ U  |2 U* P' Y1 u$ tfor mineral oil: 0.915 kg/l
9 e! ]+ i, a$ M9 B: d0 gCoil = Specific heat capacity [kJ/kgK]
! Y1 i; ~; B3 a! L5 Nfor mineral oil 1.88 kJ/kgK
0 r+ o( c+ _+ M3 w∆T = Temperature increase in the
$ q2 t. T. E, c. m/ `system [°C]
7 W5 C/ G+ s4 B# lt = Operating time [min]
T1 = Desired oil temperature [°C]
T3 = Ambient temperature [°C]
Example 1:
Measurement of the power loss
on existing units and machinery.
For this method the temperature
9 ]6 M8 h6 ^) D2 L) d% j. qincrease of the oil is measured
, `3 [$ f3 W6 c6 b4 U* Sover a certain period. The power
loss can be calculated from the
temperature increase.
- u6 v0 E, q( k  f1 yParameters:
The oil temperature increases
+ W. u1 {% W6 y5 mfrom 20 °C to 45 °C over
15 minutes.
% ?4 h4 F0 r- hThe tank contains 100 l.
Heat to be dissipated:
PV =（∆T × C oil × ρoil × V）/t × 60    [kW]
5 V) _- W0 f7 c0 q! ~3 E/ P& \; T- h; p
" R% y  V5 T+ L" cPV =25 × 1.88 × 0.915 × 100 / (15 × 60 )
7 z/ R& I- W4 v; ]9 w= 4.78 [kW]
7 e% d  k9 y6 L2 W7 ~$ lCooler selection:
( i2 k7 n  _  ?8 K. U7 P– Desired oil temperature: 60 °C
– Ambient temperature air: 30 °C

P01 =PV    /  (T1 - T3  ) [kW/°C] =0.159
A 10% safety margin is
. S9 s0 L/ U; C2 w% lrecommended to allow for
element contamination, and
therefore the specific power is:
P01 × 1.1 = 0.175 kW/°C.
( Q% y. @3 j; i  YThe power loss 0.175 kW/°C must
be dissipated by an oil cooler.
Suggestion:
–Cooler OK-ELH2 - 3000 rpm,
7 N2 G( j* {6 [: a$ s2 V9 z: MP01 = 0.20 kW/°C at 80 l/min
6 k- c8 _& U! g7 @
" J$ d- A8 |+ W% y" H1 ]7 F
5 G; T$ ^+ T. `( W3 N0 ~我發了一段在上面！