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臥式和立式機床,計算步進電機輸出的總力矩M---[求教]

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1#
發表于 2007-4-19 18:39:06 | 只看該作者 |倒序瀏覽 |閱讀模式
<SPAN lang=EN-US style="FONT-SIZE: 9pt; FONT-FAMILY: ??; mso-bidi-font-family: 宋體; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA; mso-fareast-font-family: 宋體">
<><BR style="mso-special-character: line-break">請問各位老師:</P>
<>&nbsp;&nbsp; 如果數控機械滑臺上的伺服電機改為步進電機,為選擇步進電機,<SPAN style="FONT-SIZE: 9pt; FONT-FAMILY: 宋體; mso-bidi-font-family: 宋體; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA; mso-ascii-font-family: ??; mso-hansi-font-family: ??">計算電機輸出的總力矩</SPAN><SPAN lang=EN-US style="FONT-SIZE: 9pt; FONT-FAMILY: ??; mso-bidi-font-family: 宋體; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA; mso-fareast-font-family: 宋體"><FONT face="宋體, MS Song">M時(公式如下),對于臥式和立式的機床,公式代數是否一致?對于立式機床,滑臺立置,由于滾珠絲杠沒有自鎖,Mf---<SPAN style="FONT-SIZE: 9pt; FONT-FAMILY: 宋體; mso-bidi-font-family: 宋體; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA; mso-ascii-font-family: ??; mso-hansi-font-family: ??">導軌摩擦折算至電機的轉矩 是否為零?請老師們給予幫助.謝謝啦~~</SPAN></FONT></SPAN></P>
<><SPAN lang=EN-US style="FONT-SIZE: 9pt; FONT-FAMILY: ??; mso-bidi-font-family: 宋體; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA; mso-fareast-font-family: 宋體"><FONT face="宋體, MS Song"><SPAN style="FONT-SIZE: 9pt; FONT-FAMILY: 宋體; mso-bidi-font-family: 宋體; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA; mso-ascii-font-family: ??; mso-hansi-font-family: ??"><SPAN style="FONT-SIZE: 9pt; FONT-FAMILY: 宋體; mso-bidi-font-family: 宋體; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA; mso-ascii-font-family: ??; mso-hansi-font-family: ??">計算電機輸出的總力矩</SPAN><SPAN lang=EN-US style="FONT-SIZE: 9pt; FONT-FAMILY: ??; mso-bidi-font-family: 宋體; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA; mso-fareast-font-family: 宋體"><FONT face="宋體, MS Song">M <BR><BR>M=Ma+Mf+Mt (1-3) <BR>Ma=(Jm+Jt).n/T×1.02×10ˉ2 (1-4) <BR><BR></FONT></SPAN><SPAN style="FONT-SIZE: 9pt; FONT-FAMILY: 宋體; mso-bidi-font-family: 宋體; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA; mso-ascii-font-family: ??; mso-hansi-font-family: ??">式中</SPAN><SPAN lang=EN-US style="FONT-SIZE: 9pt; FONT-FAMILY: ??; mso-bidi-font-family: 宋體; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA; mso-fareast-font-family: 宋體"><FONT face="宋體, MS Song"> <BR>Ma ---</FONT></SPAN><SPAN style="FONT-SIZE: 9pt; FONT-FAMILY: 宋體; mso-bidi-font-family: 宋體; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA; mso-ascii-font-family: ??; mso-hansi-font-family: ??">電機啟動加速力矩</SPAN><SPAN lang=EN-US style="FONT-SIZE: 9pt; FONT-FAMILY: ??; mso-bidi-font-family: 宋體; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA; mso-fareast-font-family: 宋體"><FONT face="宋體, MS Song">(N.m) <BR>Jm</FONT></SPAN><SPAN style="FONT-SIZE: 9pt; FONT-FAMILY: 宋體; mso-bidi-font-family: 宋體; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA; mso-ascii-font-family: ??; mso-hansi-font-family: ??">、</SPAN><SPAN lang=EN-US style="FONT-SIZE: 9pt; FONT-FAMILY: ??; mso-bidi-font-family: 宋體; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA; mso-fareast-font-family: 宋體"><FONT face="宋體, MS Song">Jt---</FONT></SPAN><SPAN style="FONT-SIZE: 9pt; FONT-FAMILY: 宋體; mso-bidi-font-family: 宋體; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA; mso-ascii-font-family: ??; mso-hansi-font-family: ??">電機自身慣量與負載慣量</SPAN><SPAN lang=EN-US style="FONT-SIZE: 9pt; FONT-FAMILY: ??; mso-bidi-font-family: 宋體; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA; mso-fareast-font-family: 宋體"><FONT face="宋體, MS Song">(Kg.cm.s2) <BR>n---</FONT></SPAN><SPAN style="FONT-SIZE: 9pt; FONT-FAMILY: 宋體; mso-bidi-font-family: 宋體; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA; mso-ascii-font-family: ??; mso-hansi-font-family: ??">電機所需達到的轉速</SPAN><SPAN lang=EN-US style="FONT-SIZE: 9pt; FONT-FAMILY: ??; mso-bidi-font-family: 宋體; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA; mso-fareast-font-family: 宋體"><FONT face="宋體, MS Song">(r/min) <BR>T---</FONT></SPAN><SPAN style="FONT-SIZE: 9pt; FONT-FAMILY: 宋體; mso-bidi-font-family: 宋體; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA; mso-ascii-font-family: ??; mso-hansi-font-family: ??">電機升速時間</SPAN><SPAN lang=EN-US style="FONT-SIZE: 9pt; FONT-FAMILY: ??; mso-bidi-font-family: 宋體; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA; mso-fareast-font-family: 宋體"><FONT face="宋體, MS Song">(s) <BR><BR>Mf=(u.W.s)/(2πηi)×10ˉ2 (1-5) <BR><BR>Mf---</FONT></SPAN><SPAN style="FONT-SIZE: 9pt; FONT-FAMILY: 宋體; mso-bidi-font-family: 宋體; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA; mso-ascii-font-family: ??; mso-hansi-font-family: ??">導軌摩擦折算至電機的轉矩</SPAN><SPAN lang=EN-US style="FONT-SIZE: 9pt; FONT-FAMILY: ??; mso-bidi-font-family: 宋體; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA; mso-fareast-font-family: 宋體"><FONT face="宋體, MS Song">(N.m) <BR>u---</FONT></SPAN><SPAN style="FONT-SIZE: 9pt; FONT-FAMILY: 宋體; mso-bidi-font-family: 宋體; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA; mso-ascii-font-family: ??; mso-hansi-font-family: ??">摩擦系數</SPAN><SPAN lang=EN-US style="FONT-SIZE: 9pt; FONT-FAMILY: ??; mso-bidi-font-family: 宋體; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA; mso-fareast-font-family: 宋體"><FONT face="宋體, MS Song"> <BR>η---</FONT></SPAN><SPAN style="FONT-SIZE: 9pt; FONT-FAMILY: 宋體; mso-bidi-font-family: 宋體; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA; mso-ascii-font-family: ??; mso-hansi-font-family: ??">傳遞效率</SPAN><SPAN lang=EN-US style="FONT-SIZE: 9pt; FONT-FAMILY: ??; mso-bidi-font-family: 宋體; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA; mso-fareast-font-family: 宋體"><FONT face="宋體, MS Song"> <BR><BR>Mt=(Pt.s)/(2πηi)×10ˉ2 (1-6) <BR><BR>Mt---</FONT></SPAN><SPAN style="FONT-SIZE: 9pt; FONT-FAMILY: 宋體; mso-bidi-font-family: 宋體; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA; mso-ascii-font-family: ??; mso-hansi-font-family: ??">切削力折算至電機力矩</SPAN><SPAN lang=EN-US style="FONT-SIZE: 9pt; FONT-FAMILY: ??; mso-bidi-font-family: 宋體; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA; mso-fareast-font-family: 宋體"><FONT face="宋體, MS Song">(N.m) <BR>Pt---</FONT></SPAN><SPAN style="FONT-SIZE: 9pt; FONT-FAMILY: 宋體; mso-bidi-font-family: 宋體; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA; mso-ascii-font-family: ??; mso-hansi-font-family: ??">最大切削力</SPAN><SPAN lang=EN-US style="FONT-SIZE: 9pt; FONT-FAMILY: ??; mso-bidi-font-family: 宋體; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA; mso-fareast-font-family: 宋體"><FONT face="宋體, MS Song">(N) </FONT></SPAN></SPAN></FONT></SPAN></SPAN></P>
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2#
發表于 2007-4-19 19:49:06 | 只看該作者

Re: 臥式和立式機床,計算步進電機輸出的總力矩M---[求教]

汗顏~~~~

以前我們在這方面選型的工作都是由機械工程師算的~~~~

呵呵~~~

期待高手們解答哩~~~~
3#
 樓主| 發表于 2007-4-19 21:32:17 | 只看該作者

Re: 臥式和立式機床,計算步進電機輸出的總力矩M---[求教]

我現在在做這方面的課程設計,真棘手~~

期待老師們解答~~~~
4#
 樓主| 發表于 2007-4-22 17:40:22 | 只看該作者

Re: 臥式和立式機床,計算步進電機輸出的總力矩M---[求教]

為防止滑臺下滑而安置制動器,如用制動器產生的摩擦力將滑臺和滑臺上部件的自重平衡掉,算法是否就和臥式的一樣了?請老師們給予幫助.謝謝啦~~
5#
發表于 2007-4-26 18:16:06 | 只看該作者

Re: 臥式和立式機床,計算步進電機輸出的總力矩M---[求教]

頂起來看看,瞧有沒有高手解答~~~
6#
 樓主| 發表于 2007-4-26 22:46:15 | 只看該作者

Re: 臥式和立式機床,計算步進電機輸出的總力矩M---[求教]

在臥式請況下,摩擦力是由可滑動部件重力產生的。機械滑臺和立柱連接,可以用鏈條將平衡重和滑臺的滑動部件相連接,平衡滑動部件自重。為選擇步進電機計算轉矩時,導軌摩擦折算至電機的轉矩 是否為零呢?期待高手~~
7#
發表于 2007-4-26 22:56:10 | 只看該作者

Re: 臥式和立式機床,計算步進電機輸出的總力矩M---[求教]

卷毛藝術家 網友好!

你在4樓的發言:“為防止滑臺下滑而安置制動器,如用制動器產生的摩擦力將滑臺
和滑臺上部件的自重平衡掉,算法是否就和臥式的一樣了?”

我認為不一樣,因為,臥式是克服摩擦力的問題,而立式克服的是重力加速度問題。

我不知道我的理解對否?

syw  070426---22.55
8#
發表于 2007-4-27 16:05:33 | 只看該作者

Re: 臥式和立式機床,計算步進電機輸出的總力矩M---[求教]

卷毛藝術家 網友好!

今天去了趟沈陽,在一個樓寓乘坐電梯時想到了本帖這道題,可以借用電梯做一比喻:

同等重量的電梯向上提升時用的功,和向下運動時用的功是不一樣的,因為存在
一個重力加速度。

如果,將電梯按上輪子放倒,進行前后牽引,兩個方向做的功是相同的。

syw  070427---16.05
9#
 樓主| 發表于 2007-4-27 22:43:08 | 只看該作者

Re: 臥式和立式機床,計算步進電機輸出的總力矩M---[求教]

syw開門造車  網友好!

我感覺計算Ma ---電機啟動加速力矩(N.m) 時應考慮重力加速度;

可Mf---導軌摩擦折算至電機的轉矩(N.m) 應怎樣考慮?謝謝~~

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