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公差,這兩種標注,表示意義有什么區別的?

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1#
發表于 2014-5-23 20:05:11 | 只看該作者 |倒序瀏覽 |閱讀模式
這兩種標注,表示意義有什么區別的?

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2#
發表于 2014-5-23 20:19:55 | 只看該作者
本帖最后由 HC小丁 于 2014-5-23 20:22 編輯 3 O# d2 s9 O7 T7 K$ P
5 [" a) I4 y0 v3 T1 x
基本尺寸不一樣,實際加工尺寸可能是一樣的,但設計尺寸不同
3#
發表于 2014-5-23 20:57:54 | 只看該作者
前一種標法,尺寸兩側分別加工成型,如銑或磨削兩個側面;后一種標法一般用于一個刀具完成的加工成型,如鉆孔,砂輪磨槽。
4#
發表于 2014-5-23 21:00:35 | 只看該作者
對于我們加工的來說:左圖我們會盡量把尺寸做到20.45至20.5之間
1 Q8 a+ }8 S; s                              右圖我們會盡量把尺寸做到20.4至20.45之間
2 ^& d# V7 F7 B4 T! ]  |                便于裝配
5#
發表于 2014-5-23 22:20:44 | 只看該作者
是不是根據入體原則來的?
6#
發表于 2014-5-23 22:56:22 | 只看該作者
長見識了,我原先以為是個人的習慣問題,
7#
發表于 2014-5-24 10:31:03 | 只看該作者
一般是另一個部件的基本尺寸一樣的
8#
發表于 2014-5-26 23:12:49 | 只看該作者
9.2.3 Converting Dimensions to Equal Bilateral Tolerances/ L5 O, e; }. @) I9 D8 I! }) ~
In Fig. 9-2, there were several dimensions that were toleranced using unilateral tolerances
( ]% T2 u) C- Z. u- j/ e) Y$ |(such as .375 +.000/-.031,  3.019 +.012/-.000 and .438 +.000/-.015) or unequal bilateral tolerances (such
. j7 `+ \& |7 J5 E% |as +1.500 +.010/-.004 ). If we look at the length of the shaft, we see that there are several different ways we1 j; D: k; o* Z0 q2 c7 g
could have applied the tolerances. Fig. 9-4 shows several ways we can dimension and tolerance the length) R  S; f1 \' v; q+ k- E
of the shaft to achieve the same upper and lower tolerance limits (3.031/3.019). From a design perspective,
5 L  ^6 }7 {: Z# L1 `all of these methods perform the same function. They give a boundary within which the dimension is
3 _* a* Y$ C: o& }% {) V' K- M$ pacceptable.
8 D  V1 E; b0 p) T2 c* C& e; }) Y9 \
The designer might think that changing the nominal dimension has an effect on the assembly. For' E: @% H/ X* U
example, a designer may dimension the part length as 3.019 +.012/-.000. In doing so, the designer may
  S9 \3 B& y1 cfalsely think that this will help minimize the gap for Requirement 1. A drawing, however, doesn’t give
) K$ q0 T- u3 B2 p: K* f& S7 r) rpreference to any dimension within the tolerance range.3 h. y7 W8 q' ?* S
Fig. 9-5 shows what happens to the manufacturing yield if the manufacturer “aims” for the dimension, v0 v% s& y% a5 L
stated on the drawing and the process follows the normal distribution. In this example, if the manufacturer
$ H6 m8 n0 p+ C$ {7 B' Daimed for 3.019, half of the parts would be outside of the tolerance zone. Since manufacturing shops want; b8 z& M" T$ o9 T& X
to maximize the yield of each dimension, they will aim for the nominal that yields the largest number of1 X$ `  d1 W4 s( T, I9 L
good parts. This helps them minimize their costs. In this example, the manufacturer would aim for 3.025.
+ A- I4 |% A9 P; Q9 c- qThis allows them the highest probability of making good parts. If they aimed for 3.019 or 3.031, half of the7 z$ f* B+ g: r8 n# h; D, w
manufactured parts would be outside the tolerance limits.
2 Q1 N* b: W; H- ]9 `; ?0 D& _As in the previous example, many manufacturing processes are normally distributed. Therefore, if we
+ a  [  k5 s; Y( A9 O/ W. [  ~put any unilateral, or unequal bilateral tolerances on dimensions, the manufacturer would convert them to: e9 b/ l6 m; P# d
a mean dimension with an equal bilateral tolerance. The steps for converting to an equal bilateral tolerance
5 F- E: \4 r4 ^+ A! w4 ofollow.4 k; `5 v1 ?& |* t

! i- s4 K$ P) d, ?
: u  f) v5 c5 u* ^1. Convert the dimension with tolerances to an upper limit and a lower limit. (For example, 3.028 +.003/
' n2 g" R, H( v5 c-.009 has an upper limit of 3.031 and a lower limit of 3.019.)) _) M3 a8 t7 P. V/ i! T
2. Subtract the lower limit from the upper limit to get the total tolerance band. (3.031-3.019=.012)* U- G  b8 q8 D
3. Divide the tolerance band by two to get an equal bilateral tolerance. (.012/2=.006)  k2 L& s7 H5 |1 v
4. Add the equal bilateral tolerance to the lower limit to get the mean dimension. (3.019 +.006=3.025).. s; _8 s- i/ q, {: ^
Alternately, you could subtract the equal bilateral tolerance from the upper limit. (3.031-.006=3.025)  b' Y  i" N, u* h0 |% Z
8 A6 s' \- y7 a* e0 X. k
As a rule, designers should use equal bilateral tolerances. Sometimes, using equal bilateral tolerances
) R: [9 H7 X6 d& Y6 E8 pmay force manufacturing to use nonstandard tools.  In these cases, we should not use equal bilateral& t9 g3 `+ H) ~  ]- @7 v9 P- W: \
tolerances.  For example, we would not want to convert a drilled hole diameter from Æ.125 +.005/-.001 to8 G' {0 S9 S, O
Æ.127 ±.003. In this case, we want the manufacturer to use a standard Æ.125 drill. If the manufacturer sees$ H, g3 G  o) v" }0 Y
Æ.127 on a drawing, he may think he needs to build a special tool. In the case of drilled holes, we would/ r! Q/ H. J" N) }  T
also want to use an unequal bilateral tolerance because the mean of the drilling process is usually larger
$ b% Q% _1 H3 f1 W5 b7 S: Y: D  Kthan the standard drill size. These dimensions should have a larger plus tolerance than minus tolerance.
5 z) R  I& \2 q3 x  TAs we will see later, when we convert dimensions to equal bilateral tolerances, we don’t need to keep2 q: g1 w' \0 Z  N4 ]5 x/ [2 k. o
track of which tolerances are “positive” and which tolerances are “negative” because the positive toler-- G# [8 }! W9 E$ u# v
ances are equal to the negative tolerances. This makes the analysis easier. Table 9-1 converts the neces-0 j' D' r# \6 s8 X9 `  m- Y
sary dimensions and tolerances to mean dimensions with equal bilateral tolerances.
8 e# o9 D+ q. g0 Q2 |) u5 ^
$ c- C. w5 y8 A1 G/ f6 }; K. y# O  a9 ?9 b/ Z8 ]. I0 s
"Dimensioning and Tolerancing Handbook, by Paul J. Drake, Jr."7 v+ E& B  q" O  N$ y

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9-2表中的尺寸有的具有零位偏差,有的尺寸有正負偏差。若只看軸的尺寸,可見有多種標注公差的方式。 9-4表中,尺寸的上下偏差計算值相同,但是標注不同。從設計師角度看,結果一樣的。  發表于 2014-5-30 16:57
這么吊,英文啊  發表于 2014-5-29 20:44
9#
發表于 2014-5-27 08:32:12 | 只看該作者
我來看看高手們怎么說,我對這些太不熟悉了,這幾天看書貌似看懂了,其實還是不懂
10#
發表于 2014-5-27 16:02:09 | 只看該作者
左圖,尺寸盡量避開20.4
0 d1 n) {: \8 m' Z' o, W右圖,盡量把尺寸避開20.5

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恩,我也有這么個想法,但不知怎么講的,看你你說的頓時感覺就是這個意思  發表于 2014-5-29 20:45
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