哪里有計算圓柱度誤差的程序？

deltabobchen

對呀, 三座標可以給你自動評定的呀, 你只要結果就可以了!

luxiang821

我原來也關注過一些關于形位公差評定的數學方法，不過沒學過編程很想了解實現這些方法的編程算法的一些問題。不知道有沒有人有興趣談論下，讓我也長長學問。

zhuai1003

我也不會編程，這兒有篇測量方面的文章，與大家共享

胡雷

只是 想知道這方面的計算是怎樣編程的 ，一定要知道評價的條件，在把條件列入編程   如有不對地方多多指教

hezhikai

我也在找啊

foreverhua

我會編一點 但是那個程序老是運行部出來  程序如下 請高手指點
" c9 w% S4 D' W  f2 \( Vfunction z=myfun2(x)
1 q2 c" a+ s3 o9 ul=[38.8263,35.4687,25.9806,11.9948,-4.0615,-19.4158,-31.4083,-37.9757,-37.9629,-31.4080,-19.4108,-4.0573,
% E8 |. F& V! I8 s1 d% F11.9961,25.9829,35.4653,38.8230,35.4619,25.9784,11.9957,-4.0606,-19.4149,-31.4044,-37.9785,-37.9743,-31.4093,
) X" u0 ~4 u# \! S: J+ [-19.4135,-4.0569,11.9971,25.9795,35.4636]
: p5 b" I2 s  H( r! lm=[0.0014,15.7895,28.8524,36.9273,38.6135,33.6208,22.8189,8.0678,-8.0705,-22.8217,-33.6211,-38.6107,-36.9260,
-28.8503,-15.7902,-0.0005,15.7852,28.8491,36.9245,38.6123,33.6212,22.8174,8.0687,-8.0721,-22.8214,-33.6248,
- `0 y2 X2 {4 H0 V-38.6129,-36.9251,-28.8459,-15.7876]
  B  Y' B8 r" P+ z) R& an=[-2.0010,-2.9670,-3.9326,-4.8979,-5.8630,-6.8282,-7.7937,-8.7601,-9.7259,-10.6904,-11.6543,-12.6209,-13.5862,
* E% v# K% j( C2 o! {7 K# w# w0 \/ F5 @-14.5507,-15.5175,-16.4838,-17.4502,-18.4149,-19.3811,-20.3463,-21.3115,-22.2779,-23.2418,-24.2071,-25.1726,
-26.1366,-27.1026,-28.0690,-29.0360,-30.0008]
6 t( @( z' i: ^' B6 }: O; `z=0;
) t. n$ x1 Y0 sfor k=1:30
    r(k)=(sqrt((l(k)-x(3)*n(k)-x(1))^2+(m(k)-x(4)*n(k)-x(2))^2-x(5))^2
    z=z+r(k)
: h8 m) y# ^# l0 X( z3 Kend


, M; u# k' D9 I# e2 v" ^% O
x0=[0,0,1,1,38.000];
[x,favl,exitflag,output]=fminunc(@myfun2,x0)