陽光小院暖茶 發表于 2015-5-14 13:10 ![]()
* v9 N: p! k, z0 p1 d* @不好意思，我看題目看了幾遍，還不知道這個方程是咋樣的。光括號就讓我迷糊了。幫不了你了
9 r; z% s+ } ^$ ]5 _2 a我用matlab 重新算了下 A1用t替換 B1用q替換 11/6 用替換 50用R2替換
7 w: Q: Z; |6 R8 L! |) {1 J>> syms t q a k A R2
6 }$ s5 x( _% ^' ^) P6 Y# z9 }5 z' t>> x=R2*t*sin(t)+a
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x =
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a + R2*t*sin(t)9 ~" O1 l+ x( u0 a" k/ W% s
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>> y=R2*t*cos(t)/ b! Z8 l6 u. P$ }% i/ F2 ^0 C% i
|5 `) F, `0 d0 e5 Ny =6 ?& d3 ]" Y8 D, P& V
+ z4 o+ i- Y4 g a* ~1 r% }8 i: GR2*t*cos(t)
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>> x1=-x*cos(k*q)-y*sin(k*q)+A*cos(q)
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+ T, T5 d" {- ~6 bx1 =# g; d; z* v. @4 U& G$ p4 l
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A*cos(q) - cos(k*q)*(a + R2*t*sin(t)) - R2*t*sin(k*q)*cos(t)
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>> y1=-x*sin(k*q)+y*cos(k*q)+A*sin(q)
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y1 =: L$ C f8 ]4 t
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A*sin(q) - sin(k*q)*(a + R2*t*sin(t)) + R2*t*cos(k*q)*cos(t)
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>> diff(x1,t)+ ~* E: P7 ^( }# ]0 b! p$ Z3 |
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ans =7 M* w. E) A$ V0 i
1 M# ?+ _ `! n1 J SR2*t*sin(k*q)*sin(t) - R2*sin(k*q)*cos(t) - cos(k*q)*(R2*sin(t) + R2*t*cos(t))
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& m# U" N! a5 W. y0 p8 x ]>> diff(x1,q)( Y# i4 p- f( {/ |6 v
) x7 R$ u: r# l( y* h2 Dans =1 L( p+ t7 j/ f: x* w
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k*sin(k*q)*(a + R2*t*sin(t)) - A*sin(q) - R2*k*t*cos(k*q)*cos(t)
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. X8 ?, ?- X) W& U- n8 S) {# b! S>> diff(y1,t)
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ans =
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. D, w& v( A- E4 g% s vR2*cos(k*q)*cos(t) - sin(k*q)*(R2*sin(t) + R2*t*cos(t)) - R2*t*cos(k*q)*sin(t)
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>> diff(y1,q)
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6 e* T0 R: G r2 H/ T6 j& k5 b0 {ans =
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( B% \- w Z2 k* B9 w9 JA*cos(q) - k*cos(k*q)*(a + R2*t*sin(t)) - R2*k*t*sin(k*q)*cos(t). ]; E N! ?' t. C
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>> f1=sym('(A*cos(q) - k*cos(k*q)*(a + R2*t*sin(t)) - R2*k*t*sin(k*q)*cos(t))*(R2*t*sin(k*q)*sin(t) - R2*sin(k*q)*cos(t) - cos(k*q)*(R2*sin(t) + R2*t*cos(t)))-(k*sin(k*q)*(a + R2*t*sin(t)) - A*sin(q) - R2*k*t*cos(k*q)*cos(t))*(R2*cos(k*q)*cos(t) - sin(k*q)*(R2*sin(t) + R2*t*cos(t)) - R2*t*cos(k*q)*sin(t))')! D8 z, F# d. ^, @0 G7 ]# o4 ~
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f1 =- x- X D: i) v% ^! r
% K K% I. N7 M' u
(k*cos(k*q)*(a + R2*t*sin(t)) - A*cos(q) + R2*k*t*sin(k*q)*cos(t))*(cos(k*q)*(R2*sin(t) + R2*t*cos(t)) + R2*sin(k*q)*cos(t) - R2*t*sin(k*q)*sin(t)) - (A*sin(q) - k*sin(k*q)*(a + R2*t*sin(t)) + R2*k*t*cos(k*q)*cos(t))*(sin(k*q)*(R2*sin(t) + R2*t*cos(t)) - R2*cos(k*q)*cos(t) + R2*t*cos(k*q)*sin(t))- C1 x& s3 }% G d1 F& [/ d/ u$ J
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>> simplify(f1)) x# t* b6 F- s$ i, ?/ P8 q
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ans =" I( f8 W9 F1 Y: w; N: Z* f
0 a8 y( G& m, v+ Y, VA*R2*sin(q - t - k*q) + R2^2*k*t + R2*a*k*sin(t) - A*R2*t*cos(q - t - k*q) + R2*a*k*t*cos(t)
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令 A*R2*sin(q - t - k*q) + R2^2*k*t + R2*a*k*sin(t) - A*R2*t*cos(q - t - k*q) + R2*a*k*t*cos(t)=0
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4 q5 E" c; [6 U" r7 V. u則q的表達式可手算出來
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樓主: shouce
發表于 2015-5-14 11:01:26
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