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' macro recorded on 01/16/17 by scliang
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Option Explicit '強制用戶需先聲明定義變數型態! i# k# _- `2 ^6 L0 n- V
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Dim swApp As SldWorks.SldWorks '(Early Binding)
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Dim Part As SldWorks.ModelDoc2
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Dim myModelView As ModelView 'Object 通用數據類型(Late Binding 運算速度較慢)2 t: c0 l4 Y1 L
Dim boolstatus As Boolean4 U2 O6 A+ z! q K
Dim L, L1, L2, D1, D2, M2, N1, N2 As Double
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Sub main()! c- G& h' U# V3 I/ j
Set swApp = Application.SldWorks0 G- Y) v6 \# o
Set Part = swApp.ActiveDoc% i$ B, D- Z6 a# X* d/ N
Set myModelView = Part.ActiveView
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Dim myDimension_1 As Dimension 'Object; d% N- M. B0 z5 _. `- ~( g
Dim myDimension_2 As Dimension% b2 z4 r2 y7 {8 ^( ?
Set myDimension_1 = Part.Parameter("D5@螺旋曲線/渦捲線1") '材料圈數) P) s0 A3 [2 Z0 I7 x
Set myDimension_2 = Part.Parameter("D5@螺旋曲線/渦捲線2") '彈簧圈數
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myDimension_1.SystemValue = 10( ~5 r7 A* Z+ E3 L
myDimension_2.SystemValue = 0.5" i2 I9 c( \- z j7 [
boolstatus = Part.EditRebuild3()8 |5 N# B2 O5 u" S
myModelView.RotateAboutCenter 0, 00 E2 Z# M, ]+ W6 u
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L = 3788.97938701496 '"D5@螺旋曲線/渦捲線1"+"D5@螺旋曲線/渦捲線2" 的線圈總長
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D1 = 376.996476741742 '"D5@螺旋曲線/渦捲線1" 的單圈長
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D2 = 38.0292391950834 '"D5@螺旋曲線/渦捲線2" 的單圈長0 K7 x! Y" W' Q9 U+ {
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For N2 = 1 To 25.5 Step 0.5 '彈簧圈數之循環
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myDimension_2.SystemValue = N2
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L2 = D2 * (N2 - 0.5) '"D5@螺旋曲線/渦捲線2"展開長的增量
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L1 = L - L2 '"D5@螺旋曲線/渦捲線1" 的目前展開長
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N1 = L1 / D1 '"D5@螺旋曲線/渦捲線1" 的目前圈數+ {, v& ^# p) R2 T$ ~1 Q
myDimension_1.SystemValue = N1
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boolstatus = Part.EditRebuild3()
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myModelView.RotateAboutCenter 0, 0; T# m1 M" d# q* L
Next# Q" ?) p* B( n/ u+ m
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Debug.Print "END"
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End Sub
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