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標題: 換熱器的計算---請教 [打印本頁]

作者: baboon9105    時間: 2007-11-30 11:19
標題: 換熱器的計算---請教
最近單位上新的項目,要選擇換熱器,但是如何計算?板式和管式有啥區別?
作者: olive3000    時間: 2007-12-6 21:25
管式的不好,建議選用板式的。
作者: hemei    時間: 2008-1-19 13:19
管式的冷卻面積沒有板式冷卻面積大
作者: 天涯125    時間: 2008-2-11 02:54
可以查閱化工版的機械設計手冊第4冊上面有詳細的介紹換熱面積的算法
作者: 13572593532    時間: 2008-2-11 20:23
板式的換熱效率高,不過最好選擇好一些的制造廠家.小的可以用管式的劃算.
作者: 液壓青年    時間: 2008-2-12 09:13
這得看你需要得散熱功率是多大,一般大的用板式散熱器
作者: 開達    時間: 2008-2-15 14:08
COOLER
+ G4 S: i$ W9 y9 ySELECTION
% F* _$ Y; h& ]Designation:0 @' u) u! d# S! N/ p) M, S" E& ?
PV = Power loss [kW]: K0 a" h0 e8 X0 O: Y  ?0 d# A% W
P01 = Specific cooling capacity [kW/°C]
5 {, @1 A7 }" U) N3 Q+ l# s: o, a+ aV = Tank contents [l]
7 j( g. F: `5 F4 f* n! e0 d0 Bρoil = Density of the oil [kg/l]
( J* W4 z0 l$ F( O" f; qfor mineral oil: 0.915 kg/l
/ f* g6 _& Y3 O+ b$ @8 lCoil = Specific heat capacity [kJ/kgK]
: h( l3 N  ?8 V6 \" c  kfor mineral oil 1.88 kJ/kgK0 @: T+ b* }, u! p
∆T = Temperature increase in the$ G, h# y# \4 ]& S! c  n
system [°C]9 l' [* `" O. ]# O0 c! [! p
t = Operating time [min]
" D) H: c% w# N/ U' f+ m  c; @T1 = Desired oil temperature [°C]3 F7 ?' v+ r3 \' Q! U
T3 = Ambient temperature [°C]
, w) a$ L4 t& r# JExample 1:+ O- w' i! q  G& W2 a+ E% c8 @* _
Measurement of the power loss
' s) U  E, F( J! Gon existing units and machinery.
  Y3 d# c5 ~2 ]" c! L" R* `1 {For this method the temperature
$ a' a; j( G) r6 a) k8 Nincrease of the oil is measured
  [  ~# c& J5 o0 Q9 |over a certain period. The power/ U8 o0 v, W2 _. g+ n7 A7 h  P& r
loss can be calculated from the
! H: \* o8 v6 G1 Qtemperature increase.
* q# K* e. n0 B% E% TParameters:
- c/ P+ l7 l+ a; E1 r5 V) sThe oil temperature increases, L6 w% F$ D4 P& r: r9 m
from 20 °C to 45 °C over
( x# E+ c2 w! j9 C15 minutes.# w! |! F6 d4 B8 i
The tank contains 100 l.9 E' F/ \: C. [
Heat to be dissipated:
/ ~0 V% F; i; c" HPV =(∆T × C oil × ρoil × V)/t × 60    [kW]
, ~. b* D0 n4 @! G7 |8 G
, u  N5 H& O$ k4 g# r9 WPV =25 × 1.88 × 0.915 × 100 / (15 × 60 )% F% n' q3 |+ {7 ^) T: [
= 4.78 [kW]
8 Q& l  F: a9 dCooler selection:+ E) ?* y! \  m) Y4 B
– Desired oil temperature: 60 °C
, ^, k2 c! p& X& q% J  ^– Ambient temperature air: 30 °C
$ t  K6 o- i( |2 l5 C* K8 {% m: p7 x% ^& b: W
P01 =PV    /  (T1 - T3  ) [kW/°C] =0.159
# [( x: z7 `6 v, ]% Y+ xA 10% safety margin is
( \4 f" L& l- v; z9 V; _1 F! orecommended to allow for+ T' i8 X- K4 Z
element contamination, and. B/ p( v1 l0 i7 X2 Y$ z
therefore the specific power is:
% u8 v4 ~: e. U- |P01 × 1.1 = 0.175 kW/°C.
5 f3 M1 O) @6 S8 j! _( N3 P" K! XThe power loss 0.175 kW/°C must
/ E! a* g" n2 U+ M0 W+ w; ]' lbe dissipated by an oil cooler.
6 I+ Y- ~2 i) S. J+ dSuggestion:
# v. x% d. @, M, D3 ]2 }& d+ C–Cooler OK-ELH2 - 3000 rpm,
; v$ D& o1 m3 H8 B% ?P01 = 0.20 kW/°C at 80 l/min
" O& S& M1 N, z5 q7 _! B( a# n1 L

/ x4 [  Q  f( h% n6 G* H5 c我發了一段在上面!




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