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標題: 非圓齒輪二次開發 [打印本頁]
作者: lijun1226    時間: 2016-7-8 16:10
標題: 非圓齒輪二次開發
畫齒廓，為什么最高點不在齒頂高那里。感覺不對。大家能看看我的程序嗎？Dim i As Integer
/ ^0 l& x% N2 m# T. D1 M3 Z; NReDim x0(18)
2 p- f! q& }; M9 s7 B$ I/ V" f6 sReDim y0(18)/ {8 P: g" [/ ~5 E6 ^" q

* C) l$ {4 p( {0 w% Q- g# HDim k0 As Integer
8 B; Q$ Q3 Y* T! vReDim p0(18)
. s* c+ L7 U) |. `' r- jReDim q0(18)
3 i5 F; [/ L/ h& s
7 ~  Y1 M! e( z9 QDim h0 As Integer
( h2 i7 I6 R9 i) {: }. \& EReDim p00(18)4 `% Z( e5 r4 d
ReDim q00(18)9 O5 r7 G. X1 I( K  i' Q4 l9 p

" T$ i7 e$ a2 A" @: |3 H) g: d% v3 g
$ K7 j8 i; w. [  ?u = Sqr((Da / Db) ^ 2 - 1)3 U, Q7 H4 U9 R( a  d2 p+ D
g = u / 14( G9 `7 E, _4 y; h: S, x
; }# z  ]* z+ b( f, e- t

; C) d8 a: i5 |+ ?2 U- v( g% Wxx = 0.5 * Da * Sin(Tan(f) - f)
: u/ O0 }. w3 ^! N. J+ f1 U. y3 R+ Kyy = 0.5 * Da * Cos(Tan(f) - f)' u# M2 Y8 y' K# X5 v$ h. A
( G( W! i0 B8 P/ c
7 [3 r! q( m8 @) \: q6 w( p
/ s" z1 U3 c) H6 k# M. ~$ [

& k: C, T- c  ]3 j3 Ws = pi * m / 2+ U2 X5 h" h$ m1 x( D! U; x
inva = Tan(a) - a
  ~" ?! C  D$ _9 w. K  [6 ?sb = Cos(a) * (s + m * z * inva)# ]5 ~' f' }1 l5 s! z9 w8 g
j = 2 * sb / Db
" i, @2 m" U( x( y: e
# |  k1 `  y6 ^; Lt = 0% {8 `8 K" |  c( j

4 `2 g6 K- v7 j- Z- qFor i = 1 To 14  `' c, v, B  ?8 k, x# ?

. F/ ]7 U# `8 H( ^If t <= u Then
  Y9 D# [3 y* p, ?: ~% L1 G1 T$ h* n& p/ [! o* F4 B
x0(i) = 0.5 * Db * Sin(t) - Db / 2 * t * Cos(t)
5 s0 i$ t+ u8 @* p6 [y0(i) = 0.5 * Db * Cos(t) + Db / 2 * t * Sin(t)) X) ?# l+ D: e3 Z: t5 G
( k) A: ]% \: d) f7 d; Y
p00(i) = -0.5 * Db * Sin(t) + 0.5 * Db * t * Cos(t)
1 Q  Y, S+ [; @$ nq00(i) = 0.5 * Db * Cos(t) + 0.5 * Db * t * Sin(t)
, Z1 p0 E- U+ s& _; z2 p$ t; Z% l5 U- u* {6 R- D* w' V0 O- W$ [% P
t = t + g6 B. H4 E7 o; ^' T  [
: m8 d4 r: b5 _  ^) T
p0(i) = p00(i) * Cos(j) + q00(i) * Sin(j)* ?, t6 G8 M- n2 y4 w
q0(i) = -p00(i) * Sin(j) + q00(i) * Cos(j)
4 k  e6 Y; Y! u5 n( n3 REnd If
& b3 a- ~! l& D+ U/ TNext i9 ^7 N8 |0 B! H3 k: p7 \/ \- C

  X, M% _' i2 H- i) h% ^7 aPart.SetPickMode, `/ s3 y% ?% N- {* c# C1 p/ L
xx = 0
  E1 e3 b4 W/ ^0 L+ x: dyy = 0.5 * Df1 q$ T, y9 w" F2 ]
Xx1 = xx * Cos(j) + yy * Sin(j)
- \5 D( }5 \: DYy1 = xx * Sin(j) + yy * Cos(j)/ P+ B# l% S+ E; }$ U

3 R7 Q' v' j! {: x/ @; Vp000 = -0.5 * Db * Sin(0) + 0.5 * Db * 0 * Cos(0)
' b+ ~1 b! `8 zq000 = 0.5 * Db * Cos(0) + 0.5 * Db * 0 * Sin(0); R, }% p- U2 Z
) s' e6 x: \; i8 K9 E) b  Y3 r0 A& U

7 N, V1 V) r0 G5 P: x1 H2 U9 X) X3 u
Part.SketchSpline 13, 0.001 * x0(1), 0.001 * y0(1), 0) ]' V' S+ u$ [  Y# |: x4 J# b
Part.SketchSpline 12, 0.001 * x0(2), 0.001 * y0(2), 0
6 r2 G8 q2 Y$ U  d" uPart.SketchSpline 11, 0.001 * x0(3), 0.001 * y0(3), 0
1 ^' _! a* H6 X2 l. i5 kPart.SketchSpline 10, 0.001 * x0(4), 0.001 * y0(4), 0- L+ P% [+ Y; c( v9 {
Part.SketchSpline 9, 0.001 * x0(5), 0.001 * y0(5), 0/ q7 o$ R; U) Y* L0 w3 n
Part.SketchSpline 8, 0.001 * x0(6), 0.001 * y0(6), 0
. t! u- p0 {0 T9 wPart.SketchSpline 7, 0.001 * x0(7), 0.001 * y0(7), 0
! B( k  ^% V8 A0 c! Z4 _, h$ {! b/ m+ h
Part.SketchSpline 6, 0.001 * x0(8), 0.001 * y0(8), 0
- J+ o% Y) @2 d2 VPart.SketchSpline 5, 0.001 * x0(9), 0.001 * y0(9), 0
+ W. C6 \0 a2 hPart.SketchSpline 4, 0.001 * x0(10), 0.001 * y0(10), 0# a0 ?# V! a3 K( Z$ n; H0 T! c
Part.SketchSpline 3, 0.001 * x0(11), 0.001 * y0(11), 0
  j. Q; T$ j' J) j0 LPart.SketchSpline 2, 0.001 * x0(12), 0.001 * y0(12), 0; Q0 G( C4 q5 J, |) y0 e0 Z( V( E7 L, G
Part.SketchSpline 1, 0.001 * x0(13), 0.001 * y0(13), 0
5 W/ Y' ^. a7 w- `; N; XPart.SketchSpline 0, 0.001 * x0(14), 0.001 * y0(14), 0
* x( B! f" F. i# Q& D7 ?: K* Y
4 Q5 \" }) h7 K) d# @* B$ I4 q+ X" T# ^# T6 F
Part.SketchSpline 13, 0.001 * p0(1), 0.001 * q0(1), 0
! P7 {: _) d  K! Q4 o; ePart.SketchSpline 12, 0.001 * p0(2), 0.001 * q0(2), 0
1 u: R) B* D2 c- w9 p! rPart.SketchSpline 11, 0.001 * p0(3), 0.001 * q0(3), 0
5 v7 ?5 Z8 D( f8 G) ^5 [3 uPart.SketchSpline 10, 0.001 * p0(4), 0.001 * q0(4), 03 B9 s* N8 K" z+ s0 I
Part.SketchSpline 9, 0.001 * p0(5), 0.001 * q0(5), 0. @" o" b9 d& h
Part.SketchSpline 8, 0.001 * p0(6), 0.001 * q0(6), 0
$ P& ~( q4 v( j2 Z" HPart.SketchSpline 7, 0.001 * p0(7), 0.001 * q0(7), 0
2 Y+ R  J, T2 s2 T! Y( B% S
: B  j' m2 ^* {# X1 @% }  X3 |# `1 rPart.SketchSpline 6, 0.001 * p0(8), 0.001 * q0(8), 03 k+ |& u* P& ~# K9 e, m
Part.SketchSpline 5, 0.001 * p0(9), 0.001 * q0(9), 0
9 ?/ c7 ~$ X" U6 qPart.SketchSpline 4, 0.001 * p0(10), 0.001 * q0(10), 0" Z* ^  |+ H+ P' a  z% Y
Part.SketchSpline 3, 0.001 * p0(11), 0.001 * q0(11), 07 ~8 u0 ?4 D9 A4 P- [
Part.SketchSpline 2, 0.001 * p0(12), 0.001 * q0(12), 0: ~3 _' ~' d3 O% U9 i" B
Part.SketchSpline 1, 0.001 * p0(13), 0.001 * q0(13), 09 b( b. g/ a1 v' t7 {3 N" _3 }
Part.SketchSpline 0, 0.001 * p0(14), 0.001 * q0(14), 05 z+ x3 k) H5 U7 i. o7 t
, j. a* D6 y# z6 C) h" T
作者: George_W4TBo    時間: 2016-10-2 00:47
是solidworks的二開嗎，真費勁哥都比較擯棄，這是最近做的一個單邊連續，單邊步進機構的其中一對非圓齒輪，在家里所以圖不多，有空再更新，歡迎交流



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