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標(biāo)題: 本人的畢業(yè)設(shè)計(jì)：關(guān)于UG的二次開發(fā)運(yùn)用（GRIP語(yǔ)言編程） [打印本頁(yè)]

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作者: fewofj    時(shí)間: 2011-5-27 20:21
標(biāo)題: 本人的畢業(yè)設(shè)計(jì)：關(guān)于UG的二次開發(fā)運(yùn)用（GRIP語(yǔ)言編程）

3 \$ ~' j. }" x( n8 J7 Q3 Q* [
8 s+ {: I1 D8 H8 H  [) J" e, R下面是關(guān)于凸輪的一個(gè)運(yùn)動(dòng)軌跡的編程，只要把程序?qū)氲経G中就可以實(shí)現(xiàn)凸輪的運(yùn)轉(zhuǎn)，還可以修改程序中各個(gè)凸輪的參數(shù)來(lái)實(shí)現(xiàn)各種凸輪的運(yùn)轉(zhuǎn)。組合運(yùn)動(dòng)規(guī)律
" Z$ r& @4 m1 f5 B" R0 r3 @$ }3 SENTITY/pt(360),spln(4),PT1,CR1,CR2,ext
NUMBER/J(360),S(360),X(360),Y(360),i,m,e,n
DATA/i,1,m,1,e,1,n,1  $$賦值
  x7 I9 c; q" \/ el30:
PARAM/'凸輪參數(shù)',$
; x% i% Z) Z) A# n# y# |'升程（h）',h,$
'基圓半徑（R0）',R0,$
'滾子半徑（Rr）',Rr,$
+ K5 R9 f* ~4 i/ g7 Y) R'推程轉(zhuǎn)角（Angle1）',Angle1,$
1 g, ?# [2 I2 Y1 [* W% y  d9 n4 K'遠(yuǎn)休止角（Angle2）',Angle2,$
, q5 ]# D" n6 |'回程轉(zhuǎn)角（Angle3）',Angle3,$
1 N5 [8 @* Y7 r: |0 K" Y% ~'近休止角（Angle4）',Angle4,$
, F2 `3 M/ u/ brespond
JUMP/l30:,stop:,,respond
MESSG/'您已輸入完參數(shù)！'
l00:
1 `$ s5 V" `+ g) @  xCHOOSE/'選擇推程運(yùn)動(dòng)規(guī)律',$
'一次多項(xiàng)式推程','二次多項(xiàng)式推程','五次多項(xiàng)式推程',$
'簡(jiǎn)諧運(yùn)動(dòng)推程','擺線運(yùn)動(dòng)推程',$
; f6 X8 }: Y- k( _  s& XDEFLT,1,respond
- I# C) e- e/ ^JUMP/l00:,stop:,,,lab1:,lab2:,lab3:,lab4:,lab5:,respond
, ]# v7 P- S  g) u4 J; il20:
2 D# s5 Z2 m4 x' x' XCHOOSE/'選擇回程運(yùn)動(dòng)規(guī)律',$
/ c# |/ `9 V, b2 _'一次多項(xiàng)式回程','二次多項(xiàng)式回程','五次多項(xiàng)式回程',$
( s5 a: a4 P" ^1 u'簡(jiǎn)諧運(yùn)動(dòng)回程','擺線運(yùn)動(dòng)回程',$
9 X* O# {: b/ GDEFLT,1,respond
JUMP/l20:,stop:,,,lab6:,lab7:,lab8:,lab9:,lab10:,respond
lab1:
8 z; ?$ ~0 z! e8 `) B0 BMESSG/'一次多項(xiàng)式推程'
LAA:
IFTHEN/i<Angle1+2
J(i)=i-1
  W9 b. p5 Q8 WS(i)=h*J(i)/Angle1
X(i)=(R0+S(i))*cosf(J(i))
Y(i)=(R0+S(i))*sinf(J(i))
Z=0
pt(i)=POINT/X(i),Y(i),Z
. P  Q. }( L# li=i+1
JUMP/LAA:
* P. Q- P" X0 R( W+ U/ EENDIF
spln(1)=SPLINE/pt(1..Angle1+1)
DELETE/pt(1..Angle1+1)
JUMP/l20:
0 O* }8 h3 _# ~1 d5 |$ glab2:
2 Q+ q8 Z- _# |* B; ^MESSG/'二次多項(xiàng)式推程'
$$推程等加速階段
LBB:
IFTHEN/i<Angle1/2+2
J(i)=i-1
. h0 Z% c' s& s  c3 R$ D6 j) bS(i)=2*h*J(i)*J(i)/(Angle1*Angle1)
X(i)=(R0+S(i))*cosf(J(i))
! g& Y, r# ^$ Y& c5 @Y(i)=(R0+S(i))*sinf(J(i))
$ T( p% F9 `+ l8 m; \Z=0
; R7 ]2 D) Y. N/ Z5 m' u& ~pt(i)=POINT/X(i),Y(i),Z
4 f& X' U# j  Q1 v4 I: qi=i+1
( B* f+ Z: @; r, `$ I; L2 T+ UJUMP/LBB:
ENDIF
spln(1)=SPLINE/pt(1..Angle1/2+1)
' O( K* H; v; o" w  N7 X; \, LDELETE/pt(1..Angle1/2+1)
$$推程等減速階段
LCC:
IFTHEN/e<Angle1/2+2
+ R! _" P: @' c* cJ(e)=e+Angle1/2-1
S(e)=h-2*h*(Angle1-J(e))*(Angle1-J(e))/(Angle1*Angle1)
X(e)=(R0+S(e))*cosf(J(e))
% k  O: s' z9 |# t* a$ `Y(e)=(R0+S(e))*sinf(J(e))
Z=0
6 [6 o9 |5 A7 Y! i: cpt(e)=POINT/X(e),Y(e),Z
' z+ F0 F/ p& V. se=e+1
$ g. R) q! n; OJUMP/LCC:
" X: X' u5 s7 O$ BENDIF
spln(2)=SPLINE/pt(1..Angle1/2+1)
8 U) A9 L2 E' Q4 [( W7 RDELETE/pt(1..Angle1/2+1)
JUMP/l20:
' H8 T1 }# s8 @* ^0 Klab3:
MESSG/'五次多項(xiàng)式推程'
LDD:
IFTHEN/i<Angle1+2
% k, e* t- j9 x8 m0 S$ dJ(i)=i-1
" S+ _1 \9 p5 b( ~* m4 p- ZQ=J(i)/Angle1
- L7 T' q+ i# @; z" `* |S(i)=h*(10*Q*Q*Q-15*Q*Q*Q*Q+6*Q*Q*Q*Q*Q)
X(i)=(R0+S(i))*cosf(J(i))
( i1 V8 r6 v, x+ i! w5 ZY(i)=(R0+S(i))*sinf(J(i))
Z=0
pt(i)=POINT/X(i),Y(i),Z
6 e4 j/ s% b( p- x( }6 ]i=i+1
JUMP/LDD:
ENDIF
spln(1)=SPLINE/pt(1..Angle1+1)
" S# O! Q  a- P' S, _0 ^# NDELETE/pt(1..Angle1+1)
JUMP/l20:
lab4:
MESSG/'簡(jiǎn)諧運(yùn)動(dòng)推程'
3 ]: q7 r. {0 I1 H# T1 O4 RLEE:
IFTHEN/i<Angle1+2
J(i)=i-1
S(i)=h*(1-cosf(180*J(i)/Angle1))/2
X(i)=(R0+S(i))*cosf(J(i))
. ~# n/ u* D  K- `- M; K5 xY(i)=(R0+S(i))*sinf(J(i))
% K/ }# U! ]' |9 E( g! o7 YZ=0
pt(i)=POINT/X(i),Y(i),Z
i=i+1
& i* a* f$ J8 P+ O' W- T4 N% |. y! Z2 PJUMP/LEE:
% X$ s- V8 M: z! A6 ~( mENDIF
spln(1)=SPLINE/pt(1..Angle1+1)
DELETE/pt(1..Angle1+1)
JUMP/l20:
5 O7 X+ \/ i" `lab5:
MESSG/'擺線運(yùn)動(dòng)推程'
LFF:
IFTHEN/i<Angle1+2
J(i)=i-1
S(i)=h*(J(i)/Angle1-sinf(360*J(i)/Angle1)/6.2832)
X(i)=(R0+S(i))*cosf(J(i))
Y(i)=(R0+S(i))*sinf(J(i))
Z=0
pt(i)=POINT/X(i),Y(i),Z
i=i+1
( e( M6 G. _( k: _4 r+ [/ R; U& N, xJUMP/LFF:
7 x- x: t9 X6 F' nENDIF
spln(1)=SPLINE/pt(1..Angle1+1)
DELETE/pt(1..Angle1+1)
$ T% r+ q, O: i, p( N/ M- WJUMP/l20:
+ r: m# Y- @+ }; v* b+ }lab6:
MESSG/'一次多項(xiàng)式回程'
% l: R; Y8 T( W9 q- U$ c0 lLHH:
IFTHEN/m<Angle3+2
" v7 ^% M9 ~5 n6 I3 n/ E6 x3 kJ(m)=m+Angle1+Angle2-1
5 j; A1 @+ z$ ]S(m)=h-h*(J(m)-Angle1-Angle2)/Angle3
/ [: b% h" s' P' T: B6 kX(m)=(R0+S(m))*cosf(J(m))
' d/ [2 p( x. q3 r7 C( P6 O3 DY(m)=(R0+S(m))*sinf(J(m))
0 K( ]0 c. N( s* c4 M% }1 }5 G0 \Z=0
7 Q2 x# a3 K. ]7 y# Bpt(m)=POINT/X(m),Y(m),Z
" f5 G; @3 M( jm=m+1
JUMP/LHH:
3 O0 ~2 a  ?1 `- UENDIF
" P' y" Q0 r: M: `2 n& u& |spln(2)=SPLINE/pt(1..Angle3+1)
! J" l2 m: V+ A3 n7 vDELETE/pt(1..Angle3+1)
+ @* J' s# @3 X0 `3 i, KJUMP/l40:
( C( }( I; b: R! I1 L* w1 zlab7:
8 Q4 L3 X" [6 X) h: j$ O- t' bMESSG/'二次多項(xiàng)式回程'
# O) W9 B9 }2 {# F2 J. I! y- u$$回程等減速階段
LII:
IFTHEN/m<Angle3/2+2
! ]" `4 D( ^7 q; [9 w  dJ(m)=m+Angle1+Angle2-1
, U3 N& k2 a7 T8 jS(m)=h-2*h*(J(m)-Angle1-Angle2)*(J(m)-Angle1-Angle2)/(Angle3*Angle3)
X(m)=(R0+S(m))*cosf(J(m))
Y(m)=(R0+S(m))*sinf(J(m))
$ F, B: K6 e. pZ=0
pt(m)=POINT/X(m),Y(m),Z
7 Q" o' W1 \6 o4 Xm=m+1
8 }$ _) M, d& @JUMP/LII:
  D+ l9 J+ P* U* j5 [) ?9 TENDIF
0 l/ B3 z/ Q) I8 Z" {spln(3)=SPLINE/pt(1..Angle3/2+1)
DELETE/pt(1..Angle3/2+1)
; o8 ]2 h3 e# V, E+ d6 ~8 q0 ~$$回程等加速階段
LKK:
IFTHEN/n<Angle3/2+2
6 r) y. B& M3 L! ?% V% f8 m2 BJ(n)=n+Angle1+Angle2+Angle3/2-1
Q=Angle1+Angle2+Angle3
S(n)=2*h*(Q-J(n))*(Q-J(n))/(Angle3*Angle3)
; a! p% v* G# Y! ]8 h( }X(n)=(R0+S(n))*cosf(J(n))
! Q% z# [- A9 T: @7 Y2 U) D% G4 nY(n)=(R0+S(n))*sinf(J(n))
5 r. }5 K: ~8 ]' J, CZ=0
pt(n)=POINT/X(n),Y(n),Z
n=n+1
JUMP/LKK:
# r4 z3 |" q& Q: L9 p9 Y  QENDIF
spln(4)=SPLINE/pt(1..Angle3/2+1)
DELETE/pt(1..Angle3/2+1)
/ d. S: s. @" |- T. @JUMP/l40:
6 P! Y( L  E1 ]! r+ s- G! Blab8:
2 a+ A  h- Z* w8 O! [MESSG/'五次多項(xiàng)式回程'
LRR:
" j' f$ g" j0 ?+ [) j( \+ {IFTHEN/m<Angle3+2
) H9 j$ m& W  }/ F- z5 |J(m)=m+Angle1+Angle2-1
W=(J(m)-Angle1-Angle2)/Angle3
" D7 e6 k4 D- g3 gS(m)=h-h*(10*W*W*W-15*W*W*W*W+6*W*W*W*W*W)
, X% y. D" v' C0 Z2 K: Y" hX(m)=(R0+S(m))*cosf(J(m))
; T1 w3 q; O6 _2 @$ ~' iY(m)=(R0+S(m))*sinf(J(m))
! C+ W- |5 k+ a: D$ fZ=0
pt(m)=POINT/X(m),Y(m),Z
3 N% r/ O9 s9 @! `0 z: r+ }8 Gm=m+1
/ ]( z! k0 j/ m9 P- ~6 n+ X# NJUMP/LRR:
ENDIF
7 L8 ~" V( N) p& Q  F% ]spln(2)=SPLINE/pt(1..Angle3+1)
$ u2 z5 ?4 O( I5 }DELETE/pt(1..Angle3+1)
8 _( K. u, |9 U8 b  ^JUMP/l40:
lab9:
: K7 o/ S& m& v2 m; G& sMESSG/'簡(jiǎn)諧運(yùn)動(dòng)回程'
1 c4 s2 \0 |& A+ p2 R1 `" V! nLWW:
, b& I* K/ n/ g$ OIFTHEN/m<Angle3+2
J(m)=m+Angle1+Angle2-1
S(m)=h*(1+cosf(180*(J(m)-Angle1-Angle2)/Angle3))/2
X(m)=(R0+S(m))*cosf(J(m))
Y(m)=(R0+S(m))*sinf(J(m))
0 [( T5 U3 g1 qZ=0
- W: g9 n- j4 [8 s9 K5 Rpt(m)=POINT/X(m),Y(m),Z
m=m+1
JUMP/LWW:
ENDIF
, x2 O) z6 F6 Y9 ^! Wspln(2)=SPLINE/pt(1..Angle3+1)
6 _4 g) V$ g) a6 ADELETE/pt(1..Angle3+1)
1 J+ |+ @# u1 |) N' UJUMP/l40:
3 f6 s4 z! y* q( V4 G5 d3 D- glab10:
, B8 a; Z/ D8 R+ f7 h+ AMESSG/'擺線運(yùn)動(dòng)回程'
3 `& w1 p# s, ALQQ:
IFTHEN/m<Angle3+2
& y0 {& m4 Q9 p, `J(m)=m+Angle1+Angle2-1
/ D9 t2 H1 R2 Y# u. X+ HA=J(m)-Angle1-Angle2
S(m)=h*(1-A/Angle3+sinf(360*A/Angle3)/6.2832)
X(m)=(R0+S(m))*cosf(J(m))
Y(m)=(R0+S(m))*sinf(J(m))
Z=0
pt(m)=POINT/X(m),Y(m),Z
m=m+1
- B+ e* H+ S8 x- {8 EJUMP/LQQ:
ENDIF
spln(2)=SPLINE/pt(1..Angle3+1)
DELETE/pt(1..Angle3+1)
' L! ]' k9 [& l4 PJUMP/l40:
( ~  z9 `6 p! s8 ol40:
$$遠(yuǎn)休止角
: g9 V) C7 G, t& F. nPT1=POINT/0,0
CR1=CIRCLE/CENTER,PT1,RADIUS,R0+h,START,Angle1,END,Angle1+Angle2
$$近休止角
, x0 ]; R: I* u5 kCR2=CIRCLE/CENTER,PT1,RADIUS,R0,START,Angle1+Angle2+Angle3,END,0
JUMP/stop:
stop:
halt
3 t. N6 `5 O3 K9 W+ w& ?2 M
" B4 I: ?  R& a
8 K% L8 `; M! U+ A5 V好多圖片不能上傳，如有需要的話。把郵箱給我，我可以發(fā)給他

4 G% {" O: h0 i9 `9 r0 B

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作者: 78273928    時(shí)間: 2011-6-9 11:11
13793371086@163.com    不勝感激   

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作者: fewofj    時(shí)間: 2011-6-14 21:34
回復(fù) 78273928 的帖子
. k4 x' X# F6 @4 H' O4 G
7 L. _0 T. w& ^馬上發(fā)給你。 如果收不到可以QQ聯(lián)系我：532131146

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作者: 78273928    時(shí)間: 2011-6-14 22:38
回復(fù) fewofj 的帖子
6 |  o: k8 c' L. r4 }& d' c
- @( A6 B3 E! g/ U. z謝謝 收到了  學(xué)習(xí)一下

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作者: xiaowuzh    時(shí)間: 2011-6-19 10:51
回復(fù) fewofj 的帖子
1 P0 R# z" B& S/ s* I6 b" y
樓主我郵箱的xiaowuzhi@126.com。發(fā)給我一份吧，謝謝。
6 [9 |" I4 C6 F9 W% R' N

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作者: zaq8577    時(shí)間: 2011-8-1 15:19
謝謝，正想了解一下 zaq8577@163.com

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作者: holland930    時(shí)間: 2011-8-3 11:19
799350380@qq.com  不勝感激 謝謝！

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