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標(biāo)題:
請(qǐng)教,怎樣才能用autolisp在直線兩端各加一個(gè)矩形?
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作者:
laotoule8
時(shí)間:
2024-2-7 18:01
標(biāo)題:
請(qǐng)教,怎樣才能用autolisp在直線兩端各加一個(gè)矩形?
本人不會(huì)autolisp。請(qǐng)教,怎樣才能用autolisp在直線兩端各加一個(gè)矩形?比如在白色直線的兩端各加一個(gè)1*5的矩形?
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[attach]558335[/attach][attach]558336[/attach]
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作者:
bianjun68
時(shí)間:
2024-2-8 00:13
你是直線先畫出,再加矩形,還是畫直線的同時(shí),加上矩形,一次完成?
作者:
bianjun68
時(shí)間:
2024-2-8 18:15
我用VBA實(shí)現(xiàn)。
作者:
bianjun68
時(shí)間:
2024-2-8 18:17
[attach]558339[/attach]
作者:
bianjun68
時(shí)間:
2024-2-8 18:18
Sub creatEndRect()
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Dim line2 As AcadLine
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ThisDrawing.Utility.GetEntity line2, basePnt, "Select an line:"
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Dim p1
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p1 = line2.startPoint
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Dim p2
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p2 = line2.endPoint
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Dim angle2 As Double
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angle2 = line2.angle
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Dim pts1(0 To 7) As Double
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Dim pts2(0 To 7) As Double
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pts1(0) = CDbl(p1(0)) + 0.5 * Sin(angle2): pts1(1) = CDbl(p1(1)) - 0.5 * Cos(angle2)
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pts1(2) = pts1(0) + 5 * Cos(angle2): pts1(3) = pts1(1) + 5 * Sin(angle2)
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pts1(4) = pts1(2) - 1 * Sin(angle2): pts1(5) = pts1(3) + 1 * Cos(angle2)
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pts1(6) = pts1(4) - 5 * Cos(angle2): pts1(7) = pts1(5) - 5 * Sin(angle2)
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pts2(0) = CDbl(p2(0)) + 0.5 * Sin(angle2): pts2(1) = CDbl(p2(1)) - 0.5 * Cos(angle2)
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pts2(2) = pts2(0) - 5 * Cos(angle2): pts2(3) = pts2(1) - 5 * Sin(angle2)
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pts2(4) = pts2(2) - 1 * Sin(angle2): pts2(5) = pts2(3) + 1 * Cos(angle2)
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pts2(6) = pts2(4) + 5 * Cos(angle2): pts2(7) = pts2(5) + 5 * Sin(angle2)
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Dim pl0 As AcadLWPolyline
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Set pl0 = ThisDrawing.ModelSpace.AddLightWeightPolyline(pts1)
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Dim pl1 As AcadLWPolyline
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Set pl1 = ThisDrawing.ModelSpace.AddLightWeightPolyline(pts2)
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pl0.Closed = True
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pl1.Closed = True
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End Sub
作者:
bianjun68
時(shí)間:
2024-2-12 08:21
不客氣!管用就好!
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